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Jan 20, 2021 at 10:45 vote accept iou
Jan 19, 2021 at 21:15 history became hot network question
Jan 19, 2021 at 17:10 answer added Tyler Lawson timeline score: 3
S Jan 19, 2021 at 16:13 history suggested Samuel Lelièvre CC BY-SA 4.0
Rephrase as complement to a union of spheres rather than to a set of spheres
Jan 19, 2021 at 14:48 comment added Connor Malin Alexander duality for manifolds can be refined to a statement about the Thom space of the normal bundle being stably equivalent to the complement of $X$ and a disjoint basepoint in the sphere. In fact, the stabilization need only happen once, and in your setting the stabilization has already happened since we can imagine these all embedded in a codimension 2 equator. The addition of the embeddings being uninteresting implies the normal bundles are trivial, so up to removing another point, yes the homotopy type is a wedge of spheres, probably not difficult to answer the rest from there.
Jan 19, 2021 at 14:44 answer added Danny Ruberman timeline score: 3
Jan 19, 2021 at 14:06 comment added iou @ThomasRot Right. But I'm interested in a homotopy type of a complement rather than in homology itself. Is my suggestion about a homotopy type correct? Is it a wedge of spheres?
Jan 19, 2021 at 14:04 review Suggested edits
S Jan 19, 2021 at 16:13
Jan 19, 2021 at 14:04 comment added Thomas Rot Alexander duality (en.wikipedia.org/wiki/Alexander_duality) is probably the easiest way of computing the homology of the complement.
Jan 19, 2021 at 13:12 history asked iou CC BY-SA 4.0