Skip to main content
5 events
when toggle format what by license comment
Jan 22, 2021 at 6:35 comment added Nandakumar R Thank you. I guess this gets n-1 of the 3D lattice points except the north pole on one plane. How could one possibly get a sphere to pass through n lattice points such that no 4 of them are coplanar?
Jan 22, 2021 at 4:41 comment added Noam D. Elkies Yes, but the easiest way to do that is not very exciting: start with a Schinzel circle (or some variant such as the one I gave) with n-1 points, make it the intersection of R^2 with a large sphere in R^3 whose center has a positive z-coordinate, and use the lattice generated by Z^2 and the north pole . . .
Jan 19, 2021 at 18:35 comment added Nandakumar R Thanks very much for those pointers! Just one further query: Kulikowski's proof (as given in Honsberger's 'Gems') shows how to construct a sphere such that exactly n points lie on it but those points are all coplanar. Is there a way to show the existence of a sphere in a 3D lattice such that it passes thru exactly n points, say, in general position, for any n?
Jan 19, 2021 at 12:07 history edited Alexey Ustinov CC BY-SA 4.0
added 125 characters in body
Jan 19, 2021 at 11:57 history answered Alexey Ustinov CC BY-SA 4.0