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Jan 19, 2021 at 11:40 comment added Andrei Smolensky I would say that LU and LUP decompositions are somewhat distinct from Bruhat decomposition for they work for singular matrices as well.
Jan 19, 2021 at 2:59 comment added David E Speyer You may be right.
Jan 19, 2021 at 2:30 comment added LSpice @DavidESpeyer, I thought that the term "LU decomposition" was often used even when there was a permutation involved, as in the Wikipedia article, thus allowing it to recover the whole Bruhat decomposition. I agree that, if one restricts to the literal name, then one only recovers (a translate of) the big cell.
Jan 19, 2021 at 2:14 comment added David E Speyer In various contexts, people will say that Bruhat decomposition is $\bigsqcup LwL$, $\bigsqcup LwU$, $\bigsqcup UwL$ or $\bigsqcup UwU$. This issue doesn't affect the point I am making.
Jan 19, 2021 at 2:13 comment added David E Speyer @LSpice I would say that LU decomposition is the largest piece of Bruhat decomposition. That it to say, Bruhat decomposition is $GL_n = \bigsqcup_{w \in S_n} L w U$. The $LU$ decomposition is the observation that the $w = \mathrm{Id}$ piece covers all but a piece of measure $0$.
Jan 19, 2021 at 0:10 comment added LSpice @FrancoisZiegler, isn't the LU decomposition just a translate of the Bruhat decomposition for $\operatorname{GL}_n$?
Jan 18, 2021 at 23:53 comment added wlad @FrancoisZiegler That's a good one, thanks
Jan 18, 2021 at 23:45 comment added Francois Ziegler en.wikipedia.org/wiki/Bruhat_decomposition
Jan 18, 2021 at 23:41 history edited wlad CC BY-SA 4.0
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Jan 18, 2021 at 23:40 history undeleted wlad
Jan 18, 2021 at 23:06 history deleted wlad via Vote
Jan 18, 2021 at 23:01 comment added wlad Question author here: It looks like the RRQR decomposition is an example
Jan 18, 2021 at 23:00 history asked wlad CC BY-SA 4.0