Timeline for Cutting a Julia set into infinitely many pieces at finitely many points
Current License: CC BY-SA 4.0
3 events
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| Jan 15, 2021 at 21:03 | comment | added | Lasse Rempe | @JimBelk If you have infinitely many accesses from the same invariant component to a periodic point, then you should basically be in the same situation as in the polynomial case. On the other hand, you should not be able to have a point accessible from infinitely many different Fatou components. | |
| Jan 15, 2021 at 18:14 | comment | added | Jim Belk | Thanks for the answer. Do you have an idea for how the argument would go in the rational hyperbolic case? There aren't external rays to work with, and it's hard to see how to prove anything about connectivity when you don't have the Carathéodory loop. | |
| Jan 15, 2021 at 17:52 | history | answered | Lasse Rempe | CC BY-SA 4.0 |