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when toggle format what by license comment
May 2, 2022 at 3:01 history edited Michael Hardy CC BY-SA 4.0
"plain" ---> "plane"
Jan 17, 2021 at 1:45 answer added Iosif Pinelis timeline score: 0
Jan 16, 2021 at 22:41 vote accept Rafael
Jan 16, 2021 at 22:41 vote accept Rafael
Jan 16, 2021 at 22:41
Jan 16, 2021 at 22:41 vote accept Rafael
Jan 16, 2021 at 22:41
Jan 15, 2021 at 5:03 answer added Iosif Pinelis timeline score: 0
Jan 14, 2021 at 16:52 answer added Iosif Pinelis timeline score: 5
Jan 14, 2021 at 14:46 comment added Rafael It's because $(\vec{y},Q\vec{y})=\sum_{i=1}^{k}y_i^2-\frac{1}{k}(\sum_{i=1}^{k}y_i)^2$ and we are subject to the bound $\sum_{i=1}^{k}y_i=x$
Jan 14, 2021 at 13:10 comment added thedude In your Method 2 the quantity $(\vec{y},Q\vec{y})$ is supposed to be equal to $\sum_i y_i^2-x^2/k$? I don't see this
Jan 14, 2021 at 11:18 history edited YCor CC BY-SA 4.0
removed capitals from title
Jan 14, 2021 at 8:09 answer added Carlo Beenakker timeline score: 1
Jan 14, 2021 at 6:41 history asked Rafael CC BY-SA 4.0