Timeline for If $x \ge 0$ and $\mathbf{1}^Tx \le \|x\|^2$ then $\mathbf{1}^T(I - xx^T / \|x\|^2) \mathbf{1} \ge \| [\mathbf{1} - x]_+ \|^2$
Current License: CC BY-SA 4.0
5 events
when toggle format | what | by | license | comment | |
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Jan 12, 2021 at 18:39 | answer | added | Iosif Pinelis | timeline score: 3 | |
Jan 12, 2021 at 18:10 | answer | added | Richard Zhang | timeline score: 3 | |
Jan 12, 2021 at 16:09 | comment | added | Richard Zhang | In 1 dimension it is trivial. But even in 2 dimensions it's not very obvious. | |
Jan 12, 2021 at 16:07 | comment | added | Jukka Kohonen | Can you prove it easily in low dimension, say, 1, 2 or 3? | |
Jan 12, 2021 at 15:44 | history | asked | Richard Zhang | CC BY-SA 4.0 |