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Timeline for Can we solve this ODE?

Current License: CC BY-SA 4.0

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Jan 15, 2021 at 22:14 vote accept Kung Yao
Jan 15, 2021 at 19:56 answer added მამუკა ჯიბლაძე timeline score: 3
Jan 12, 2021 at 18:12 comment added Will Jagy found an undergraduate project on Floquet, fse.studenttheses.ub.rug.nl/17640/1/bMATH_2018_FolkersE.pdf Not sure yet if we can explicitly calculate the monodromy matrix if we cannot explicitly write down a fundamental matrix
Jan 12, 2021 at 2:29 comment added Will Jagy Look up Floquet theory for periodic coefficients en.wikipedia.org/wiki/Floquet_theory
Jan 11, 2021 at 19:35 comment added Christian Remling Variable coefficient linear ODEs as a general rule don't have explicit solutions as soon as the order exceeds $1$.
Jan 11, 2021 at 19:23 comment added Pietro Majer In general, $\big(e^{B(x)}\big)'$ is not $e^{B(x)}B'(x)$ nor $B'(x)e^{B(x)}$, unless $B$ and $B'$ commute
Jan 11, 2021 at 19:21 comment added Will Jagy @მამუკაჯიბლაძე it works when the coefficient matrix commutes with its derivative
Jan 11, 2021 at 19:18 comment added მამუკა ჯიბლაძე Yes, you are right. By some reason I expected that $y$ and the antiderivative would commute, but now I cannot actually find any reason to expect it.
Jan 11, 2021 at 19:01 comment added Kung Yao @მამუკაჯიბლაძე mhmm, but so what you did is that you computed the antiderivative $B(x)$ of the matrix, let's call it $A(x)$. But this way wouldn't we have. So $y(x) = exp(B(x))$ but then $y'(x)= y(x)A(x)$ by the chain rule. So why is this the same as $A(x)y(x)$?
Jan 11, 2021 at 18:55 comment added მამუკა ჯიბლაძე This is completely standard except for matrices: $\frac{dy}y=(\text{your matrix})dx$ gives$$y=\exp\left(\left(\begin{smallmatrix}0&x+\sin(x+\frac\pi4)\\x-\sin(x-\frac\pi4)&0\end{smallmatrix}\right)+\text{any constant matrix}\right)$$
Jan 11, 2021 at 18:50 comment added Mateusz Kwaśnicki Mathematica 10.0 does not seem to give any closed-form solution.
Jan 11, 2021 at 18:42 history asked Kung Yao CC BY-SA 4.0