Timeline for What's so special about the forgetful functor from G-rep to Vect?
Current License: CC BY-SA 2.5
6 events
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| Jun 25, 2023 at 23:37 | comment | added | LSpice | Direct link to @pasqualezito's answer. | |
| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Jul 19, 2011 at 9:23 | comment | added | David Corfield | Presumably supergroups appear here for the same kind of reason that supergroupoids appear in '2-Hilbert Spaces' arxiv.org/abs/q-alg/9609018, e.g., where Baez and Dolan prove "a generalized Doplicher-Roberts theorem stating that every symmetric 2-$H^{\ast}$-algebra is equivalent to the category $Rep(G)$ of continuous unitary finite-dimensional representations of some compact supergroupoid $G$." | |
| Sep 8, 2010 at 20:33 | comment | added | Theo Johnson-Freyd | Oh, OK! So I should demand that my functor to Vect be symmetric monoidal. The Ostrik paper is a nice one. | |
| Sep 8, 2010 at 19:40 | comment | added | David Jordan | The last sentence probably follows from Deligne's theorem which says that a symmetric tensor category satisfying certain growth properties in the length of its objects under iterated tensor product is necessarily RepG for a super group G, and which group it is is determined by the symmetric structure. A very nice exposition, in English, is here: arxiv.org/abs/math/0401347 | |
| Sep 8, 2010 at 19:30 | history | answered | David Jordan | CC BY-SA 2.5 |