It does not yet appear possible. Please let me explain.
Einstein's GR postulates the equality of a curvature tensor $R_{ij}-R g_{ij}$ with a mass-energy quantity of the form $\kappa T_{ij}$ where $T$ is a term representing mass-energy. That is $R_{ij}-Rg_{ij}=\kappa T_{ij}$
The answerequality demands:
Hypothesis (i) that the LHS term of Einstein's GR equation $R_{ij}-Rg_{ij}$ is Noan invariant tensor, and has vanishing tensor divergence $div(R_{ij}-Rg_{ij})=0$. (And this is true, as observedverified by Dirac, Eddingtoncalculations).
Hypothesis (ii): that the RHS mass-energy quantity $T_{ij}$ be a tensor quantity, and Einstein himselfthat $T_{ij}$ have well-defined tensor divergence which vanishes identically.
The GR equation appears to be well formed only if (see references belowii) is satisfied.
In Einstein's formulation of GR (1916) an expression for the mass energy $T$ was given, but which failed to satisfy (ii). The key pointerror is thatan improper index contraction. The master of the absolute differential calculus, Levi-Civita corrected Einstein's mathematicaloriginal expression $t^\alpha_\sigma$ for the so-called "energy components" $t^\alpha_\sigma$ of the gravitational fieldfields. Levi-Civita's form of GR equations yields proper tensor divergences $div T$ if $T$ is not tensorial. The nonSee Ch.XI, SS 20-tensoriality of25 in Levi-Civita's "Absolute Differential Calculus". However Levi-Civita's appears to confuse mass with matter, invoking the energy components impliescontinuity equation of incompressible fluid flow as parallel for the energy field cannot be localized and hasdensity using $e=mc^2=\rho c^2$. But we see no observer-independant componentsreason why mass needs satisfy a continuity equation. For we acknowledge that matter is neither created nor destroyed, but mass is mutable. This is controversial, relating to Newton's definition of mass as a measure of matter.
PThe tensoriality of $T$ is not readily established, being dependant on the physical model used.
As far as Einstein's original expression $t=t^\alpha_\sigma$, P.A.M. Dirac said ``in general, gravitational energy cannot be localized. The best we can do is use a pseudotensor...which gives us approximate information about gravitational energy, which in some special cases can be accurate." (See Dirac's book "General Theory of Relativity").
Dirac says further, "Let us consider the energy of these waves. Oweing to the pseudo-tensor not being a real tensor, we do not get, in general, a clear result independant of the coordinate system. But there is one special case in which we do get a clear result; namely when the waves are all moving in the same direction", (Ibid).
Any person interested in further critical analysis is well recommended to see Section 8 of Crothers' article https://vixra.org/abs/1804.0399 and also https://vixra.org/abs/1103.0051 . (This author's own critical reviewSo as of the above articles finds them very informativeyet, and with very clear treatment of differential geometrythe answer to the OP's question appears Negative.