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Jan 5, 2021 at 3:43 comment added sharpe Oh, I see. It certainly looks like no good.
Jan 5, 2021 at 2:17 comment added BigbearZzz @sharpe unfortunately, for any continuous approximation of $f\in W^{1,p}(\Omega)$, the factor $1/r$ would blow up the error term. I haven't found a way to make it works yet.
Jan 5, 2021 at 2:08 comment added sharpe I don't know well. At least if $p=2$, it follows that $C(\overline{D}) \cap W^{1,2}(D)$ is a dense subspace of $W^{1,2}(D)$. Wouldn't it work if we used this fact?
Jan 4, 2021 at 18:56 comment added BigbearZzz @sharpe very interesting, thanks! This piqued my interest quite a bit. Do you know if a similar result holds when $f$ is a Sobolev function instead?
Jan 4, 2021 at 11:21 comment added sharpe If $\Omega$ is a bounded Lipschitz domain, we have $\lim_{r \to 0}(1/r)\int_{\Omega_r}f(y)\,dy=\int_{\partial \Omega}f(y)\,d\mathcal{H}^{n-1}(y)$ for any bounded continuous function $f \colon \overline{\Omega} \to \mathbb{R}$. See Lemma 7.1 in this article projecteuclid.org/download/pdfview_1/euclid.aop/1485421330.
Jan 4, 2021 at 10:41 history asked BigbearZzz CC BY-SA 4.0