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Sep 27, 2021 at 19:03 history edited varkor CC BY-SA 4.0
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Jan 5, 2021 at 12:29 comment added Tim Campion Er -- rather, that other question is not-so-tangentially related -- it's the dual of the special case where the monoidal structure is cocartesian.
Jan 5, 2021 at 0:00 vote accept varkor
Jan 4, 2021 at 2:00 history became hot network question
Jan 3, 2021 at 23:04 answer added Tim Campion timeline score: 20
Jan 3, 2021 at 21:12 comment added Tim Campion Reminds me of a tangentially related question.
Jan 3, 2021 at 21:01 answer added Qiaochu Yuan timeline score: 22
Jan 3, 2021 at 20:55 comment added Noah Snyder @QiaochuYuan: Ah, right. In my setting, one looks at the Deligne-Kelly tensor product of the two categories rather than their Cartesian product, and so the functor out of that is also right exact.
Jan 3, 2021 at 20:49 comment added Qiaochu Yuan @Noah: usually tensor product is right exact in each argument; varkor is asking for an adjoint of the entire functor of two arguments, not an adjoint in one argument or the other.
Jan 3, 2021 at 20:47 comment added Noah Snyder This probably won't help you. What I'm familiar with is a related question which is when the right adjoint (which usually automatically exists under the assumptions people typically work in for tensor categories) has the structure of a strong module functor. See Section 4.1 of arxiv.org/pdf/1804.07538.pdf and Appendix D of people.math.harvard.edu/~gaitsgde/GL/shvsofcat.pdf
Jan 3, 2021 at 20:36 comment added varkor @NoahSnyder: the concept is intended to be a weakening of the notion of cartesian category (where the cartesian product is right adjoint to the diagonal). However, one could just as well ask for a right adjoint instead, which would correspond to the cocartesian setting. I'm happy to know of references for either.
Jan 3, 2021 at 20:28 comment added Noah Snyder Usually tensor product is right exact, not left exact. Are you sure you want to be asking for a left adjoint here and not a right adjoint?
Jan 3, 2021 at 17:57 history asked varkor CC BY-SA 4.0