Timeline for If $\mu_t\to\mu$ weakly, then $\limsup_t|\mu_t|(A)\le|\mu|(A)$ for all closed $A$
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 1, 2021 at 5:15 | vote | accept | 0xbadf00d | ||
| Jan 1, 2021 at 5:15 | comment | added | 0xbadf00d | Interestingly ... Why aren't we able to find such counterexamples for the somehow complementary result $(2)$ as well? | |
| Dec 31, 2020 at 19:13 | comment | added | Iosif Pinelis | @NateEldredge : Indeed, your example is better: just one quick up-and-down suffices. | |
| Dec 31, 2020 at 19:10 | comment | added | Nate Eldredge | Another counterexample, I think, is $\mu_n = \delta_{1/n} - \delta_{-1/n}$, $\mu=0$. | |
| Dec 31, 2020 at 18:56 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |