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Dec 30, 2020 at 23:35 vote accept gigi
Dec 30, 2020 at 21:29 answer added Wojowu timeline score: 8
Dec 30, 2020 at 21:07 history edited gigi CC BY-SA 4.0
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Dec 30, 2020 at 20:58 comment added gigi @FedorPetrov oh I see what you mean, now I think the notation problem is fixed. Thank you!
Dec 30, 2020 at 20:57 history edited gigi CC BY-SA 4.0
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Dec 30, 2020 at 20:32 comment added Fedor Petrov $\lim_{n \rightarrow \infty}(\prod_{i=1}^{n}i^{\chi(i \: \text{mod} 2\mathbb{Z})})^{-1}$ - if $n$ is even yes, but if $n$ is odd no.
Dec 30, 2020 at 19:28 history edited gigi CC BY-SA 4.0
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Dec 30, 2020 at 19:26 comment added gigi @YemonChoi yeah sure, I'll fix it. Thank you.
Dec 30, 2020 at 19:16 comment added Yemon Choi Something is wrong with your notation. Even if we can give meaning to the expression $\prod_{n\in {\bf N}} n^{\chi(n+2{\bf Z})}$, you can't take the "limit of this as $n$ tends to infinity" because $n$ is a "bound variable" or "dummy variable" rather than an outside parameter
Dec 30, 2020 at 19:07 history asked gigi CC BY-SA 4.0