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Jan 2, 2021 at 21:18 history edited Vladimir Reshetnikov CC BY-SA 4.0
[Edit removed during grace period]
Dec 31, 2020 at 16:13 history edited Vladimir Reshetnikov CC BY-SA 4.0
typesetting
Dec 31, 2020 at 16:11 vote accept Vladimir Reshetnikov
Dec 30, 2020 at 18:46 history edited Vladimir Reshetnikov CC BY-SA 4.0
Rephrasing of some definitions, and improved typesetting
Dec 30, 2020 at 18:14 history edited Vladimir Reshetnikov CC BY-SA 4.0
Better typesetting and coloring of formulae
Dec 30, 2020 at 18:07 comment added Vladimir Reshetnikov @dodd Sorry, I inadvertently dropped 2 quantifiers $\forall s\,\exists w$ when I typed the last formula. $s$ is any set, and $w$ is a superset of its transitive closure under $\prec$ relation, and the whole formula says $w$ exists for any $s$, provided that $\prec$ is set-like. Thanks for the correction, I fixed the formula.
Dec 30, 2020 at 18:03 history edited Vladimir Reshetnikov CC BY-SA 4.0
Add missing quantifiers
S Dec 30, 2020 at 9:49 history suggested gmvh
Added top-level tag
Dec 30, 2020 at 9:21 review Suggested edits
S Dec 30, 2020 at 9:49
Dec 30, 2020 at 7:31 history became hot network question
Dec 30, 2020 at 6:06 comment added markvs If you believe that your axioms imply the axiom of infinity, you may want to present a proof here. Your last line of OP is not clear to me. What is $s$?
Dec 30, 2020 at 2:33 comment added Vladimir Reshetnikov @dodd Sorry, I made some significant corrections and clarifications to my question. Do you make the same claim about the corrected version?
Dec 30, 2020 at 2:28 history edited Vladimir Reshetnikov CC BY-SA 4.0
deleted 6 characters in body
Dec 30, 2020 at 2:21 comment added Vladimir Reshetnikov @HanulJeon The Replacement says that if we replace each element of a set by exactly one object, then the result is still a set. This "bolder" version asserts that we can replace an element not only by a single object, but by all elements of any set, and even if such replacement is repeated transitively, we still have a set at the end.
Dec 30, 2020 at 2:16 comment added Vladimir Reshetnikov @PaceNielsen I updated my question to express my idea more clearly. There is a proposed formalization for the transitive closure not using a notion of an infinite set or a union. I believe, the last axiom is strong enough to imply Axioms of Infinity and Union.
Dec 30, 2020 at 2:10 history edited Vladimir Reshetnikov CC BY-SA 4.0
The last axiom corrected and formalized
Dec 30, 2020 at 1:00 answer added Elliot Glazer timeline score: 12
Dec 30, 2020 at 0:34 comment added markvs The class consisting of all finite sets satisfies your axioms but not ZFC.
Dec 29, 2020 at 23:53 comment added Hanul Jeon Could you explain why your last axiom schema is a bolder version of Replacement?
Dec 29, 2020 at 23:39 comment added Pace Nielsen How are you defining the transitive closure of a relation without the axiom of infinity?
Dec 29, 2020 at 23:39 comment added Vladimir Reshetnikov The last axiom schema can be thought of as a bolder version of Replacement.
Dec 29, 2020 at 23:25 history asked Vladimir Reshetnikov CC BY-SA 4.0