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Dec 24, 2020 at 20:37 comment added Adittya Chaudhuri I got it. Thank you Sir very much.
Dec 24, 2020 at 20:37 history edited Dmitri Pavlov CC BY-SA 4.0
added 33 characters in body
Dec 24, 2020 at 20:35 comment added Dmitri Pavlov @AdittyaChaudhuri: Yes. This also follows directly from the fact that surjective homomorphisms of Lie groups are submersions. Since any simplicial Lie group is a Kan complex, the matching maps are surjective homomorphisms of Lie groups, hence surjective submersions.
Dec 24, 2020 at 20:33 comment added Adittya Chaudhuri Thank you very much Sir for the reference. So, are you saying that a simplicial Lie group is naturally a Kan simplicial manifold because of example 6 in your answer? Or am I misunderstanding something?
Dec 24, 2020 at 20:30 history edited Dmitri Pavlov CC BY-SA 4.0
added 78 characters in body
Dec 24, 2020 at 20:28 comment added Dmitri Pavlov @AdittyaChaudhuri: Simplicial groups are a special case of Example 6. See Carrasco and Cegarro, Group-theoretic algebraic models for homotopy types.
Dec 24, 2020 at 20:27 comment added Adittya Chaudhuri Thank you very much Sir.
Dec 24, 2020 at 20:23 comment added Dmitri Pavlov @AdittyaChaudhuri: This is Corollary 2.2 in arxiv.org/abs/math/0609420v6
Dec 24, 2020 at 20:07 comment added Adittya Chaudhuri Sir, we know that every simplicial group is a Kan complex. Is it true that every simplicial Lie group is a Kan fibrant simplicial manifold? (If its true, then it can be an another example)
Dec 24, 2020 at 19:53 comment added Adittya Chaudhuri Thank you Sir. Can you please suggest some literatures where I can get some details of the statement "This follows from the fact that Hom(Λ^m_j, X) can be presented as the domain of a finite sequence of base changes of surjective submersions" in your last comment?
Dec 24, 2020 at 19:50 comment added Adittya Chaudhuri Sir, I edited "wedge" symbol to "capital Lambda" symbol in my question.
Dec 24, 2020 at 19:34 comment added Dmitri Pavlov @AdittyaChaudhuri: Yes, Hom(Λ^m_j, X) is a smooth manifold for any Kan simplicial manifold X, in particular, it is a smooth manifold in all examples given above. (Do note that Λ is the capital Greek letter lambda, not the wedge sign ∧.) This follows from the fact that Hom(Λ^m_j, X) can be presented as the domain of a finite sequence of base changes of surjective submersions. Since surjective submersions of smooth manifolds are closed under base changes along arbitrary smooth maps, this establishes the claim.
Dec 24, 2020 at 19:26 comment added Adittya Chaudhuri Thank you very much Sir for the answer. Sir, does that mean that in each of these examples $Hom(\wedge_{j}^m,X)$ is a smooth manifold? (Since we need the restriction maps $Hom(\Delta^{m},X) \rightarrow Hom(\wedge^{m}_{j}, X)$ to be surjective submersions for all $m \in \mathbb{N} \cup \lbrace 0 \rbrace $ and $0 \leq j \leq m$ by definition of Kan simplicial manifolds. Is there any canonical smooth manifold structure on the Hom sets $Hom(\wedge_{j}^m,X)$? (Here $X$ is the Kan simplicial manifold)
Dec 24, 2020 at 19:17 vote accept Adittya Chaudhuri
Dec 24, 2020 at 19:06 history answered Dmitri Pavlov CC BY-SA 4.0