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Dec 24, 2020 at 17:07 comment added Simon Henry My previous description of the topology was wrong: I had the wrong definition of condensed sets in mind. Now that I checked the definition, it is fixed.
Dec 24, 2020 at 17:06 history edited Simon Henry CC BY-SA 4.0
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Dec 24, 2020 at 16:37 comment added Simon Henry It seems so yes. More generally, every open covering.
Dec 24, 2020 at 16:37 history edited Simon Henry CC BY-SA 4.0
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Dec 24, 2020 at 16:12 comment added Steven Gubkin Thanks, this is very useful (especially the link to the comparison lemma). So we would have (for instance), the injections of intervals $(n,n+2) \subset \mathbb{R} $ as a valid covering of the reals.
Dec 24, 2020 at 16:09 vote accept Steven Gubkin
Dec 24, 2020 at 2:55 comment added Simon Henry I've added a spelled out description of the topology one need to use one the category of spaces for the equivalence to work, but I'm not sure which kind of details you want.
Dec 24, 2020 at 2:55 history edited Simon Henry CC BY-SA 4.0
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Dec 24, 2020 at 2:13 comment added Steven Gubkin Thanks for this answer. I am definitely a noob at all of this stuff (I have not thought about a topos since I was an undergraduate). Would you be willing to spell out the details a little more?
Dec 24, 2020 at 1:56 history answered Simon Henry CC BY-SA 4.0