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May 23 at 20:32 history edited Tom Copeland CC BY-SA 4.0
Correct shift in argument of the Hurwitz zeta function added.
Jan 23, 2023 at 6:14 comment added Tom Copeland @TymaGaidash, roughly you are neglecting that $1/t$ tends to infinity as $t$ tends to $0$. Review the use of delta functions and the Gelfand-Shilov rep. Other more elementary intros to generalized functions and regularization of integrals are useful (Kanwal maybe).
Jan 23, 2023 at 3:06 comment added Тyma Gaidash @TomCopeland If $f(x)=\sum\limits_{n=0}^\infty \int_0^\infty f(t) t^{-n-1}dt \frac{(-x)^n}{n!(-n-1)!}$ does not have the MMT cancel the $(-n-1)!$, then those sum terms are $0$ from $\sum\limits_{n=0}^\infty (\dots)\frac1{(-n-1)!}$. Is there any way to prevent this?
Mar 23, 2021 at 0:23 history edited Tom Copeland CC BY-SA 4.0
added the hypergeometric functions
Feb 24, 2021 at 18:26 history edited Tom Copeland CC BY-SA 4.0
Added Mellin transform of Gaussian for reference in other answers
Feb 5, 2021 at 21:28 comment added Tom Copeland A relation to Newton interpolation, which often has a larger region of convergence than the MMT, is given in mathoverflow.net/questions/192146/…
Feb 5, 2021 at 21:15 history edited Tom Copeland CC BY-SA 4.0
Introduced examples of application of the RMF
Jan 23, 2021 at 19:52 comment added Tom Copeland Another simple application of the RMF is illustrated in mathoverflow.net/questions/381935/…
Dec 26, 2020 at 14:35 history edited Tom Copeland CC BY-SA 4.0
Commented on focus of my answer
Dec 22, 2020 at 2:40 comment added FFjet Thx, I'll read it.
Dec 22, 2020 at 2:35 comment added Tom Copeland As usual, one has to be careful about signs, so I put a little more detail in an answer to the the related MO-Q mathoverflow.net/questions/353282/…
Dec 22, 2020 at 2:28 comment added FFjet Thanks for your answer and suggestions. I'll pay attention to that next time.
Dec 22, 2020 at 2:26 vote accept FFjet
Dec 21, 2020 at 19:58 history edited Tom Copeland CC BY-SA 4.0
Corrected notation
Dec 21, 2020 at 19:37 history answered Tom Copeland CC BY-SA 4.0