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Dec 17, 2020 at 23:46 comment added SashaP If such $R_X$ exists then Hochschild homology of $X$ is concentrated in non-negative homological degrees. In characteristic zero HKR theorem (for smooth $X$) $HH_i(X)=\bigoplus\limits_{p-q=i}H^q(X,\Omega^p)$ then implies that $H^q(X,\Omega^p)=0$ for $q>p$. If $X$ is smooth proper this implies that $H^{p,q}(X)=0$ when $p\neq q$, so the cohomology of such smooth proper variety would have to be Tate.
Dec 17, 2020 at 20:13 comment added Aaron Bergman Well, for what it's worth, I believe all the del Pezzos have tilting objects and I believe Craw has proved it true for a class of toric varieties. I know more has been done, but I'd just end up googling "tilting object" and "tilting sheaf" to get a more up-to-date answer.
Dec 17, 2020 at 19:09 comment added Mikhail Bondarko I am not willing to go to dg algebras since this will not yield a t-structure.:) And I have a trivial family of examples: one can certainly take $X$ to be an affine variety.
Dec 17, 2020 at 19:07 comment added Aaron Bergman If you're willing to go to dg-algebras, I think smooth and proper is enough by Bondal and Van Den Bergh arxiv.org/abs/math/0204218
Dec 17, 2020 at 19:01 comment added Leo Alonso It may well be that this is only possible when the varieties are cohomologically simple, projective spaces, grassmannians, quadrics. I doubt there is such description in "general type" varieties, but this is just a guess.
Dec 17, 2020 at 16:42 history asked Mikhail Bondarko CC BY-SA 4.0