Skip to main content
added 225 characters in body
Source Link

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

By sendingLet \begin{align} f: M &\rightarrow \mathbb{Z}_2\\ f(a,b) & \mapsto a+b \end{align}

$f$ maps a cocycle2-cocycle in $t \in Z^2(G,\mathbb{Z}_2)$$Z^2(G,M)$ to $(t,t) \in Z^2(G,M)$ we see thata 2-coycle in $Z^2(G,\mathbb{Z}_2)$. I want an example where the image of $f$ is not a subgroup ofcoboundary.

Examples I have checked:

$H^2(\mathbb{Z}_2, M) = 0$ for $Z^2(G,M)$$\pi = \text{id}$.

What's an example of a groupI have also checked numerically that $G$$H^2(\mathbb{Z}_2 \times \mathbb{Z}_2, M)$ for $\pi(a,b) = a+b$ and normalized cocycle in $Z^2(G,M)$ which is not in the subgroup$\pi(a,b)=a$ also only have images that are coboundaries under $Z^2(G,\mathbb{Z}_2)$?$f$.

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

By sending a cocycle $t \in Z^2(G,\mathbb{Z}_2)$ to $(t,t) \in Z^2(G,M)$ we see that $Z^2(G,\mathbb{Z}_2)$ is a subgroup of $Z^2(G,M)$.

What's an example of a group $G$ and normalized cocycle in $Z^2(G,M)$ which is not in the subgroup $Z^2(G,\mathbb{Z}_2)$?

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

Let \begin{align} f: M &\rightarrow \mathbb{Z}_2\\ f(a,b) & \mapsto a+b \end{align}

$f$ maps a 2-cocycle in $Z^2(G,M)$ to a 2-coycle in $Z^2(G,\mathbb{Z}_2)$. I want an example where the image of $f$ is not a coboundary.

Examples I have checked:

$H^2(\mathbb{Z}_2, M) = 0$ for $\pi = \text{id}$.

I have also checked numerically that $H^2(\mathbb{Z}_2 \times \mathbb{Z}_2, M)$ for $\pi(a,b) = a+b$ and $\pi(a,b)=a$ also only have images that are coboundaries under $f$.

deleted 42 characters in body
Source Link

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

By sending a cocycle $t \in Z^2(G,\mathbb{Z}_2)$ to $(t,t) \in Z^2(G,M)$ we see that $Z^2(G,\mathbb{Z}_2)$ is a subgroup of $Z^2(G,M)$.

When is $Z^2(G,M)/Z^2(G,\mathbb{Z}_2)$ non-trivial?

What's an example of a group $G$ and normalized cocycle in $Z^2(G,M)$ which is not in the subgroup $Z^2(G,\mathbb{Z}_2)$?

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

By sending a cocycle $t \in Z^2(G,\mathbb{Z}_2)$ to $(t,t) \in Z^2(G,M)$ we see that $Z^2(G,\mathbb{Z}_2)$ is a subgroup of $Z^2(G,M)$.

When is $Z^2(G,M)/Z^2(G,\mathbb{Z}_2)$ non-trivial?

What's an example of a normalized cocycle in $Z^2(G,M)$ which is not in the subgroup $Z^2(G,\mathbb{Z}_2)$?

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

By sending a cocycle $t \in Z^2(G,\mathbb{Z}_2)$ to $(t,t) \in Z^2(G,M)$ we see that $Z^2(G,\mathbb{Z}_2)$ is a subgroup of $Z^2(G,M)$.

What's an example of a group $G$ and normalized cocycle in $Z^2(G,M)$ which is not in the subgroup $Z^2(G,\mathbb{Z}_2)$?

edited body
Source Link

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

By sending a cocycle $t \in Z^2(G,\mathbb{Z}_2)$ to $(t,t) \in H^2(G,M)$$(t,t) \in Z^2(G,M)$ we see that $Z^2(G,\mathbb{Z}_2)$ is a subgroup of $H^2(G,M)$$Z^2(G,M)$.

When is $H^2(G,M)/Z^2(G,\mathbb{Z}_2)$$Z^2(G,M)/Z^2(G,\mathbb{Z}_2)$ non-trivial?

What's an example of a normalized cocycle in $H^2(G,M)$$Z^2(G,M)$ which is not in the subgroup $Z^2(G,\mathbb{Z}_2)$?

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

By sending a cocycle $t \in Z^2(G,\mathbb{Z}_2)$ to $(t,t) \in H^2(G,M)$ we see that $Z^2(G,\mathbb{Z}_2)$ is a subgroup of $H^2(G,M)$.

When is $H^2(G,M)/Z^2(G,\mathbb{Z}_2)$ non-trivial?

What's an example of a normalized cocycle in $H^2(G,M)$ which is not in the subgroup $Z^2(G,\mathbb{Z}_2)$?

Let $G$ be a finite group; denote by $\mathbb{Z}_2$ the cyclic group of order $2$. Let $\pi: G \rightarrow \mathbb{Z}_2$ be a non-trivial group homomorphism. Let M be the $G$ representation $\mathbb{Z}_2 \times \mathbb{Z}_2$ with action given by \begin{align} g[(a,b)] = \begin{cases} (a,b)& \quad \text{if $\pi(g) = 0$}\\ (b,a)& \quad \text{if $\pi(g) = 1$}. \end{cases} \end{align}

By sending a cocycle $t \in Z^2(G,\mathbb{Z}_2)$ to $(t,t) \in Z^2(G,M)$ we see that $Z^2(G,\mathbb{Z}_2)$ is a subgroup of $Z^2(G,M)$.

When is $Z^2(G,M)/Z^2(G,\mathbb{Z}_2)$ non-trivial?

What's an example of a normalized cocycle in $Z^2(G,M)$ which is not in the subgroup $Z^2(G,\mathbb{Z}_2)$?

edited body
Source Link
Loading
added notation
Source Link
YCor
  • 63.9k
  • 5
  • 187
  • 286
Loading
deleted 350 characters in body
Source Link
Loading
added 11 characters in body
Source Link
Loading
added 376 characters in body
Source Link
Loading
added 150 characters in body
Source Link
Loading
Source Link
Loading