Timeline for How to prove surjectivity of biharmonic operator?
Current License: CC BY-SA 4.0
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Dec 16, 2020 at 8:41 | history | edited | fatemeh sharifi | CC BY-SA 4.0 |
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Dec 15, 2020 at 15:36 | comment | added | fatemeh sharifi | Dear Jochen, thanks for your comment. I've added the boundary conditions to the question's post. Since they are all equal to zero, after integration by parts they disappeared. Please note that I used the notation 'bending moment' $M_{x}, M_{y}$ and shear force $Q_{x},Q_{y}$ instead of 'displacement field' $h$, which have second and third order derivative of the displacement field. For more details about the notation, please see the paper with DOI:10.1016/j.apm.2019.04.036. I used integration by parts and showed the symmetry. But regarding the surjectivity I don't have any clue in my mind! | |
Dec 15, 2020 at 15:23 | history | edited | fatemeh sharifi | CC BY-SA 4.0 |
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Dec 15, 2020 at 10:12 | comment | added | Jochen Glueck | Crossposted from Mathematics Stack Exchange. Please explicitly mention and link the crosspost within your question in such a case. | |
Dec 15, 2020 at 9:58 | history | edited | Jochen Glueck | CC BY-SA 4.0 |
Fixed a typoe.
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Dec 15, 2020 at 9:57 | comment | added | Jochen Glueck | Welcome to MathOverflow! First a remark concerning the symmetry: The domain of your operator is too large, i.e., it does not encode any boundary conditions; this implies that the operator is actually not symmetric (in order to prove symmetry, you need to integrate by parts, and there you need certain $0$-boundary conditions which ensure that the occurring boundary terms vanish). | |
Dec 15, 2020 at 9:53 | history | edited | fatemeh sharifi | CC BY-SA 4.0 |
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Dec 15, 2020 at 9:26 | review | First posts | |||
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Dec 15, 2020 at 9:20 | history | asked | fatemeh sharifi | CC BY-SA 4.0 |