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Dec 15, 2020 at 16:12 comment added Dirk Werner Bill, no problem!
Dec 14, 2020 at 19:56 comment added Bill Johnson I see. Sorry, Dirk.
Dec 14, 2020 at 15:11 comment added Dirk Werner @Bill: I think I said so in my answer...
Dec 14, 2020 at 14:38 comment added Bill Johnson More generally, if $K$ is a compact Hausdorff space for which $C(K)$ is a Grothendieck space, then every convergent sequence in $K$ is eventually constant.
Dec 14, 2020 at 0:10 vote accept Dongyang Chen
Dec 13, 2020 at 19:51 comment added Yemon Choi Nice - I like this argument better than my original suggestion, since it seems to pinpoint the key "largeness" property required for a given $\Omega$ to yield the Grothendieck space property for $C(\Omega)$
Dec 13, 2020 at 19:31 history answered Dirk Werner CC BY-SA 4.0