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Dec 10, 2020 at 19:58 comment added asv @ChristianRemling : What is wrong with the exponent?
Dec 10, 2020 at 16:47 comment added Christian Remling On the other hand, without growth restrictions at infinity, no conclusions can be drawn (for example $D=-d^2/dx^2+1$ has the solutions $u=e^{\pm x}$).
Dec 10, 2020 at 16:03 comment added Giorgio Metafune You are right: if such a $u$ belongs to ${\cal S}'(R^n)$, then $u=0$.
Dec 10, 2020 at 15:58 history edited asv CC BY-SA 4.0
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Dec 10, 2020 at 15:48 history asked asv CC BY-SA 4.0