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Dec 4, 2020 at 18:39 comment added Marcel K. Goh @Seva I just came to the realisation that for my problem specifically, I only need very loose bounds, so that would definitely work. However, this is an interesting question in general (perhaps even replacing ${\bf Z}/n{\bf Z}$ with an arbitrary abelian group), and I'd be happy to hear anything that sheds light on it!
Dec 4, 2020 at 7:39 comment added Seva The upper bound $kn^\varepsilon$ is easy; would you be happy with it? It is probably close to what one can prove, anyway.
Dec 4, 2020 at 0:13 history asked Marcel K. Goh CC BY-SA 4.0