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Nov 30, 2020 at 23:10 history became hot network question
Nov 30, 2020 at 16:41 vote accept Mikhail Borovoi
Nov 30, 2020 at 16:03 answer added YCor timeline score: 8
Nov 30, 2020 at 15:46 comment added Mikhail Borovoi @YCor: Thank you, that is an answer!
Nov 30, 2020 at 15:40 comment added YCor Just from the table: $i(jk)=j(ki)=k(ij)=-i(kj)=-j(ik)=-k(ji)=-1$...
Nov 30, 2020 at 15:27 comment added Mikhail Borovoi @YCor: Yes, it is clearly invariant and alternating. How did you compute the value on $(i,j,k)$?
Nov 30, 2020 at 15:21 history edited Mikhail Borovoi CC BY-SA 4.0
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Nov 30, 2020 at 15:20 comment added YCor What about $(x,y,z)\mapsto\mathrm{Re}(x(yz)+y(zx)+z(xy)-x(zy)-y(xz)-z(yx))$? It's clearly invariant alternating. On $(i,j,k)$ its value is $-6$, so it's nonzero.
Nov 30, 2020 at 15:07 history asked Mikhail Borovoi CC BY-SA 4.0