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Feb 25, 2022 at 15:18 history edited coudy CC BY-SA 4.0
correct spelling
May 29, 2012 at 20:06 history edited Pietro Majer CC BY-SA 3.0
edited body
Sep 6, 2010 at 19:46 comment added Dorian Also, for the $d=2$ case, consider the function $u(x) = \log |x|$. Then $|Du(x)| = \frac{1}{|x|}$ and so $\int |Du(x)|^2 = 2\pi \int_0^r r^2/r$ which is finite obviously. So $\log|x|$ is in $H_0^1(\Omega)$ but not continuous. A similar example can be made for $d=3$ with $1/|x|^{\alpha}$ for an appropriate choice of $\alpha > 0$.
Sep 6, 2010 at 19:19 comment added alext87 Cheers! :) The first one $d=1$ is simple doing it this way. Now off to find out about the co-area formula...
Sep 5, 2010 at 2:48 history answered Dorian CC BY-SA 2.5