Timeline for Growth of eigenvalues for certain sequences of matrices

13 events

when toggle format	what		by	license	comment
Dec 5, 2020 at 22:25	vote	accept	Zestylemonzi
S Dec 5, 2020 at 22:25	history	bounty ended	Zestylemonzi
S Dec 5, 2020 at 22:25	history	notice removed	Zestylemonzi
Dec 1, 2020 at 15:30	answer	added	Fabian Wirth		timeline score: 1
S Dec 1, 2020 at 14:35	history	bounty started	Zestylemonzi
S Dec 1, 2020 at 14:35	history	notice added	Zestylemonzi		Draw attention
Dec 1, 2020 at 14:35	history	edited	Zestylemonzi	CC BY-SA 4.0	added 8 characters in body
Dec 1, 2020 at 14:26	history	edited	Zestylemonzi	CC BY-SA 4.0	added 63 characters in body
Nov 30, 2020 at 14:57	comment	added	user35593		yes it only works for $t\rightarrow -\infty$ sorry
Nov 30, 2020 at 13:39	comment	added	Zestylemonzi		Thanks for your reply, but I'm confused by your comment - the expression $\Lambda(A_{e^t})=e^t\Lambda(B) + O(e^{2t})$ is an asymptotic expression where the "error term" $e^{2t}$ is larger than the "lead term" $e^t$ as $t \to\infty$.
Nov 30, 2020 at 13:09	comment	added	user35593		We have $A_t=tB+O(t^2)$. Then we have $\Lambda(A_{e^t})=e^t\Lambda(B)+O(e^{2t})$. Hence $log \Lambda(A_{e^t})=t+log(\Lambda(B))+O(e^{t})$. Hence if $B\neq 0$, $\alpha_2=1$ and error is $log(\Lambda(B))$.
Nov 30, 2020 at 11:16	history	edited	Zestylemonzi	CC BY-SA 4.0	added 283 characters in body
Nov 26, 2020 at 23:22	history	asked	Zestylemonzi	CC BY-SA 4.0