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Sep 4, 2010 at 13:56 vote accept CommunityBot
Sep 4, 2010 at 13:56
Sep 4, 2010 at 12:49 comment added Joseph O'Rourke @Jose: Yes, what you say holds in the smooth category. I guess that was implied; sorry. So consider my comment just a remark that without that assumption, the situation alters.
Sep 4, 2010 at 12:46 history edited José Figueroa-O'Farrill CC BY-SA 2.5
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Sep 4, 2010 at 12:42 comment added José Figueroa-O'Farrill @Joseph: Guilty as charged! But aren't we in the smooth category? At least that is what I understood from the way the question was phrased.
Sep 4, 2010 at 12:19 comment added Joseph O'Rourke @Jose: I believe your statement is correct only with the additional qualification that the embedding is smooth? Zalgaller has constructed an isometric embedding of the flat torus. See my answer to this MO question: mathoverflow.net/questions/31222/… . I think in your proof sketch the conclusion that the curvatures agree at the contact point requires the embedding to be smooth.
Sep 4, 2010 at 11:21 history answered José Figueroa-O'Farrill CC BY-SA 2.5