Timeline for Nash embedding theorem for 2D manifolds
Current License: CC BY-SA 2.5
18 events
when toggle format | what | by | license | comment | |
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Oct 12, 2010 at 0:23 | answer | added | Will Jagy | timeline score: 3 | |
Sep 12, 2010 at 5:51 | comment | added | Daniel Barter | @Robin Chapman: I think it is proved in the last chapter of Do Carmo's book "The differential Geometry of curves and surfaces" | |
Sep 8, 2010 at 2:12 | answer | added | Bill Thurston | timeline score: 54 | |
Sep 7, 2010 at 21:28 | comment | added | Deane Yang | Anton's point is a very good one. | |
S Sep 7, 2010 at 1:46 | vote | accept | CommunityBot | ||
S Sep 7, 2010 at 1:46 | vote | accept | CommunityBot | ||
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Sep 5, 2010 at 2:57 | comment | added | Anton Petrunin | BTW, the local version of your question is still open. Namely, is it true that any point on a surface has a nbhd which admits a smooth isometric embedding into $\mathbb R^3$? | |
Sep 4, 2010 at 14:04 | answer | added | Deane Yang | timeline score: 16 | |
Sep 4, 2010 at 13:56 | vote | accept | CommunityBot | ||
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S Sep 4, 2010 at 13:56 | vote | accept | CommunityBot | ||
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Sep 4, 2010 at 13:56 | vote | accept | CommunityBot | ||
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Sep 4, 2010 at 12:47 | answer | added | Joseph O'Rourke | timeline score: 23 | |
Sep 4, 2010 at 12:19 | comment | added | Joseph O'Rourke | See also this related MO question: mathoverflow.net/questions/31222/… | |
Sep 4, 2010 at 12:06 | answer | added | BS. | timeline score: 5 | |
Sep 4, 2010 at 11:35 | answer | added | Dror Atariah | timeline score: 1 | |
Sep 4, 2010 at 11:21 | answer | added | José Figueroa-O'Farrill | timeline score: 7 | |
Sep 4, 2010 at 10:35 | comment | added | Robin Chapman | Certainly one can't embed any compact non-orientable manifold in $\mathbb{R}^3$. It's well-known that one can't embed the hyperbolic plane isometrically in $\mathbb{R}^3$, but I don't know a convenient reference for this off-hand. | |
Sep 4, 2010 at 10:17 | history | asked | user39719 | CC BY-SA 2.5 |