Skip to main content
18 events
when toggle format what by license comment
Oct 12, 2010 at 0:23 answer added Will Jagy timeline score: 3
Sep 12, 2010 at 5:51 comment added Daniel Barter @Robin Chapman: I think it is proved in the last chapter of Do Carmo's book "The differential Geometry of curves and surfaces"
Sep 8, 2010 at 2:12 answer added Bill Thurston timeline score: 54
Sep 7, 2010 at 21:28 comment added Deane Yang Anton's point is a very good one.
S Sep 7, 2010 at 1:46 vote accept CommunityBot
S Sep 7, 2010 at 1:46 vote accept CommunityBot
S Sep 7, 2010 at 1:46
Sep 5, 2010 at 2:57 comment added Anton Petrunin BTW, the local version of your question is still open. Namely, is it true that any point on a surface has a nbhd which admits a smooth isometric embedding into $\mathbb R^3$?
Sep 4, 2010 at 14:04 answer added Deane Yang timeline score: 16
Sep 4, 2010 at 13:56 vote accept CommunityBot
S Sep 7, 2010 at 1:46
S Sep 4, 2010 at 13:56 vote accept CommunityBot
Sep 4, 2010 at 13:56
Sep 4, 2010 at 13:56 vote accept CommunityBot
S Sep 4, 2010 at 13:56
Sep 4, 2010 at 12:47 answer added Joseph O'Rourke timeline score: 23
Sep 4, 2010 at 12:19 comment added Joseph O'Rourke See also this related MO question: mathoverflow.net/questions/31222/…
Sep 4, 2010 at 12:06 answer added BS. timeline score: 5
Sep 4, 2010 at 11:35 answer added Dror Atariah timeline score: 1
Sep 4, 2010 at 11:21 answer added José Figueroa-O'Farrill timeline score: 7
Sep 4, 2010 at 10:35 comment added Robin Chapman Certainly one can't embed any compact non-orientable manifold in $\mathbb{R}^3$. It's well-known that one can't embed the hyperbolic plane isometrically in $\mathbb{R}^3$, but I don't know a convenient reference for this off-hand.
Sep 4, 2010 at 10:17 history asked user39719 CC BY-SA 2.5