Timeline for Is this lower bound on the singular values of the sum of two matrices correct?
Current License: CC BY-SA 4.0
12 events
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| Dec 24, 2023 at 23:38 | comment | added | AlkaKadri | I think I found the resolution to the above concerns (see my answer below). There's no expectation of the matrices being psd (though the inequality as stated is incorrect). | |
| Dec 24, 2023 at 23:34 | answer | added | AlkaKadri | timeline score: 2 | |
| Nov 18, 2020 at 10:35 | comment | added | Federico Poloni | The answer box is a little lower. Show that you are not afraid of downvotes and post your answers as answers. :) | |
| Nov 18, 2020 at 0:31 | comment | added | Narutaka OZAWA | That's Weyl inequality when $A$ and $B$ are hermitian. | |
| Nov 17, 2020 at 19:45 | comment | added | Anthony Quas | I think the title of paper gives a hint that the matrices are expected to be positive semi definite. | |
| Nov 17, 2020 at 18:39 | history | edited | darij grinberg | CC BY-SA 4.0 |
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| Nov 17, 2020 at 17:16 | comment | added | Mikael de la Salle | No. Take $B$ the identity and $A=-B$. Your inequality reads $0 \geq 2$. | |
| Nov 17, 2020 at 16:42 | history | edited | Rodrigo de Azevedo | CC BY-SA 4.0 |
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| Nov 17, 2020 at 16:28 | comment | added | Gabriele Oliva | I see. But in this case $\sigma_j(0)=0\geq \sigma_j(A)-\lambda_1(A)$. I think this is possible. | |
| Nov 17, 2020 at 16:20 | comment | added | Anthony Quas | Seems a little tough if $B=-A$. | |
| Nov 17, 2020 at 16:17 | review | First posts | |||
| Nov 17, 2020 at 18:38 | |||||
| Nov 17, 2020 at 16:16 | history | asked | Gabriele Oliva | CC BY-SA 4.0 |