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Nov 23, 2020 at 9:02 vote accept user102868
Nov 20, 2020 at 18:01 comment added user111 only $\zeta_n$ I guess.
Nov 20, 2020 at 16:34 comment added user102868 From the answer of Gerry Myerson, the answer seem to be $\sim \zeta_nV(f^2)$ or is it $$\sim \zeta_n^mV(f^2)$$
Nov 16, 2020 at 13:22 comment added user102868 Thanks for the answer. I think its the same for $m>1$ too.
Nov 16, 2020 at 12:36 history edited user111 CC BY-SA 4.0
link to another MO question added
Nov 15, 2020 at 18:18 history answered user111 CC BY-SA 4.0