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Nov 15, 2020 at 15:37 vote accept swami
Nov 12, 2020 at 21:26 answer added Lucia timeline score: 13
Nov 12, 2020 at 18:19 answer added Sylvain JULIEN timeline score: 2
Nov 12, 2020 at 14:12 answer added Carlo Beenakker timeline score: 9
Nov 12, 2020 at 12:17 comment added Carlo Beenakker so the question is equivalent to asking whether $nH_{n}-mH_{m}$ can be an integer for $n\neq m$; note that it is known that the difference $H_{n}-H_{m}$ of two different harmonic numbers cannot be an integer, perhaps the proof can be applied to this question as well
Nov 12, 2020 at 12:16 comment added Sylvain JULIEN Perhaps we could first show this holds for all integers sharing the same radical. Given an integer $n$ the smallest integer $n'$ greater than $n$ with the same radical is $2n$, but then from Bertrand's postulate a new prime appears among the $k$ one sums over, hence giving rise to a new denominator for the rational number the considered fractional part is equal to.
Nov 12, 2020 at 11:56 comment added Carlo Beenakker true up to $n=10^4$
Nov 12, 2020 at 11:50 history asked swami CC BY-SA 4.0