Timeline for Prove that the real part of this limit converges to $\frac{1}{2}$
Current License: CC BY-SA 4.0
22 events
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Feb 13, 2023 at 14:08 | answer | added | Mats Granvik | timeline score: 0 | |
Jan 26, 2023 at 18:00 | answer | added | Mats Granvik | timeline score: 0 | |
Jan 25, 2023 at 6:24 | history | edited | David Roberts♦ | CC BY-SA 4.0 |
Reformatted giant equation
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Jan 25, 2023 at 5:08 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Sep 27, 2022 at 5:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
May 30, 2022 at 4:05 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jan 30, 2022 at 3:08 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Oct 2, 2021 at 3:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Dec 9, 2020 at 18:41 | answer | added | Mats Granvik | timeline score: 1 | |
Nov 25, 2020 at 1:44 | comment | added | Gottfried Helms |
Use Pari/GP with default(realprecision,200) to get the same digits as for the Mathematica-value
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Nov 24, 2020 at 16:54 | answer | added | Mats Granvik | timeline score: 1 | |
Nov 9, 2020 at 12:26 | comment | added | Henri Cohen | @GH: I have looked in standard refs, and did not find this formula. It is not very efficient, but it would be interesting to have some sort of proof. | |
Nov 8, 2020 at 20:59 | comment | added | GH from MO | @HenriCohen: Sure, but why is that? Can you give any references or insight? | |
Nov 7, 2020 at 21:42 | comment | added | Henri Cohen | This has nothing to do with zeta: try it with other functions, it gives very good approximations to a zero. | |
Nov 7, 2020 at 18:30 | history | edited | GH from MO |
edited tags
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Nov 7, 2020 at 18:26 | comment | added | GH from MO | It seems that if you start with an arbitrary $s$, your expression converges to a nearby zero of $\zeta$. Very curious (hence interesting). The first 100 billion nontrivial zeros of $\zeta$ are known to have real part $1/2$. See also plouffe.fr/simon/constants/zeta100.html | |
Nov 7, 2020 at 17:40 | comment | added | Fedor Petrov | Why do you need $1/n$ (and also why $+s$ in LHS but not $1/6$ on the right)? | |
Nov 7, 2020 at 16:36 | comment | added | Mats Granvik | I changed it to the regular size now. | |
Nov 7, 2020 at 16:35 | history | edited | Mats Granvik | CC BY-SA 4.0 |
deleted 6 characters in body
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Nov 7, 2020 at 16:34 | comment | added | Ben McKay | Perhaps the biggest typeset equation I have every seen. I wonder what the biggest equation ever published was. | |
Nov 7, 2020 at 16:29 | history | edited | Mats Granvik | CC BY-SA 4.0 |
added 79 characters in body
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Nov 7, 2020 at 16:23 | history | asked | Mats Granvik | CC BY-SA 4.0 |