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Nov 8, 2020 at 11:13 history edited Mateusz Kwaśnicki CC BY-SA 4.0
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Nov 8, 2020 at 11:12 comment added Mateusz Kwaśnicki Yes, sorry for all these typos. I was typing in a hurry.
Nov 7, 2020 at 16:49 vote accept Julian Newman
Nov 7, 2020 at 16:49 comment added Julian Newman Thank you! Where you say $A>1$ and $B<1$, I guess it's meant to say $A>\frac{1}{3}$ and $B<\frac{1}{3}$? Anyway, this is really, really useful for me.
Nov 7, 2020 at 11:18 comment added Mateusz Kwaśnicki Right, of course! Fixed, hopefully.
Nov 7, 2020 at 11:17 history edited Mateusz Kwaśnicki CC BY-SA 4.0
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Nov 6, 2020 at 23:32 comment added Julian Newman Thank you very much. But I'm confused about the line $(\log g'(x))' = \sum_{i = 1}^n (\log f_i'(x_i))' = \sum_{i = 1}^n \frac{f_i''(x_i)}{f_i'(x_i)}$. Since $x_i$ is itself a function of $x$, are you not missing factors in front of $\frac{f_i''(x_i)}{f_i'(x_i)}$?
Nov 6, 2020 at 22:44 history answered Mateusz Kwaśnicki CC BY-SA 4.0