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Dec 17, 2020 at 0:11 history edited Nourddine Snanou CC BY-SA 4.0
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Nov 13, 2020 at 21:44 history edited Nourddine Snanou CC BY-SA 4.0
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Nov 13, 2020 at 21:34 history edited Nourddine Snanou CC BY-SA 4.0
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Nov 13, 2020 at 20:46 history edited LSpice CC BY-SA 4.0
Removed spurious space after editing
Nov 13, 2020 at 18:33 history edited Nourddine Snanou CC BY-SA 4.0
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Nov 7, 2020 at 0:34 history edited LSpice CC BY-SA 4.0
Title and proofreading (and deleted 'thank you')
Nov 6, 2020 at 21:14 comment added YCor Note that for $p=2,3$ there are elements of order $p^2$ too.
Nov 6, 2020 at 20:29 history edited Nourddine Snanou CC BY-SA 4.0
edited title
Nov 6, 2020 at 20:03 comment added Derek Holt If it's any help, the answers (to both questions) when $p=2,3,5,7$ are $6,10,12,12$. That's as far as I can go with naive computation.
Nov 6, 2020 at 19:59 comment added Nourddine Snanou @Derek Holt, thank you for your comment. Of course f is injective.
Nov 6, 2020 at 19:52 history edited Nourddine Snanou CC BY-SA 4.0
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Nov 6, 2020 at 19:50 comment added Derek Holt I am not sure that I believe that knowing just the number of isomorphism classes of semidirect products will enable you to compute the number of conjugacy classes of subgroups $C_p^2$ in ${\rm GL} (4,p)$. Not all of the homomorphisms $f$ are injective. Also, it is not clear (to me) that the isomorphism of two of the semidirect products would imply the conjugacy of the corresponding subgroups of ${\rm GL} (4,p)$.
Nov 6, 2020 at 19:44 history edited Nourddine Snanou CC BY-SA 4.0
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Nov 6, 2020 at 19:30 comment added YCor The title seems distinct from the question (even if there is a relation). If there is a reduction from the main question to the title question, please incorporate in the question.
Nov 6, 2020 at 19:29 history edited YCor CC BY-SA 4.0
formatting
Nov 6, 2020 at 19:26 history asked Nourddine Snanou CC BY-SA 4.0