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Sep 5, 2010 at 5:40 vote accept umar
Sep 4, 2010 at 7:12 vote accept umar
Sep 4, 2010 at 7:12
Sep 3, 2010 at 20:09 answer added umar timeline score: 2
Sep 3, 2010 at 11:21 answer added Bob Durrant timeline score: 1
Sep 3, 2010 at 10:11 comment added J. M. isn't a mathematician umar: An $m\times n$ matrix has $\min(m,n)$ singular values.
Sep 3, 2010 at 8:02 comment added umar J.M. -- Thanks. I don't understand your claim that $\phi(A) = \sigma_{min}(A^T)$ when $m < n$. Isn't it the case that $\sigma_{min}(A^T) = \sigma_{min}(A)$? So doesn't my $m = 1$ and $n > 1$ counterexample still apply?
Sep 3, 2010 at 6:20 comment added J. M. isn't a mathematician "although I am not certain why this is true" - books on numerical linear algebra devote a paragraph or two to this, since this is related to the discussion of the conditioning of least squares problems.
Sep 3, 2010 at 6:19 comment added J. M. isn't a mathematician For $m<n$, $\sigma_{\min}$ of $A^T$ is your $\phi$.
Sep 3, 2010 at 5:27 history asked umar CC BY-SA 2.5