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Nov 5, 2020 at 19:25 comment added esg @Anush: Sorry, I have no idea what the lower bound should be for $k=3$ or any other odd $k$. (I have only found a construction which gives slightly lower (asymptotically equivalent) bounds than in the $k=4$ case.)
Nov 5, 2020 at 10:15 history bounty ended Simd
Nov 5, 2020 at 6:30 comment added Simd For k=3, is it possible to say what the lower bound is?
Nov 4, 2020 at 20:21 comment added esg In the sum in my previous comment the upper index should be $k-1$ (sorry for the typo!).
Nov 4, 2020 at 18:08 comment added Gabe K So for pairwise independence ($k=2$) the other question showed that as $d$ gets large a strict lower bound is $1/d$ so it seems like these arguments are contradicting each other.
Nov 4, 2020 at 17:27 comment added esg For $k$ fixed and $d \longrightarrow \infty$ the bounds converge to $\sum_{i=0}^k \frac{(-1)^i}{i!}$
Nov 4, 2020 at 15:01 comment added Gabe K What are the asymptorics in $k$ and $d$ here? Is there a simple expression?
Nov 4, 2020 at 14:47 history answered esg CC BY-SA 4.0