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Nov 4, 2020 at 20:08 comment added Samantha @losif Pinellas, I posted a new question here link
Nov 4, 2020 at 18:50 history edited Iosif Pinelis CC BY-SA 4.0
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Nov 4, 2020 at 18:40 vote accept Samantha
Nov 4, 2020 at 18:34 comment added Iosif Pinelis @Samantha : In your question, it was assumed that $a$ and $b$ are arbitrary real numbers. As such, your question has been fully answered (negatively). If you want to pursue this further and impose further conditions, then you should ask such additional questions in separate posts. Anyhow, as now shown in the edited answer, your function is not analytic for any real $a$ and $b$ unless $a=b=0$.
Nov 4, 2020 at 18:32 history edited Iosif Pinelis CC BY-SA 4.0
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Nov 4, 2020 at 18:09 comment added Samantha @losif Pinellas By looking at the equation, I think for non-zero $a$, $b$ both $\Im g(s,t)[=0]$=$\Re g(s,t)[=0]$ and will satisfy Cauchy Raman equations.. And Hence it will be analytic in the bounded complex plane. Am I right?
Nov 4, 2020 at 17:56 comment added Samantha @losif Pinellas, if $a$ and $b$ both are positive (non-zero) can I say f is analytic on the complex plane?
Nov 4, 2020 at 14:13 history edited Iosif Pinelis CC BY-SA 4.0
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Nov 4, 2020 at 13:44 history edited Iosif Pinelis CC BY-SA 4.0
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Nov 4, 2020 at 13:35 history edited Iosif Pinelis CC BY-SA 4.0
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Nov 4, 2020 at 13:03 history answered Iosif Pinelis CC BY-SA 4.0