Timeline for Expected number of lines meeting four given lines or "what is 1.72..."
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Nov 5, 2020 at 15:18 | comment | added | Moritz Firsching | This is really amazing! It now works. (I assume that there's a factor $pi^4$ between $\delta_{1, 3}$ and $\operatorname{edeg}G(2,4)$, i.e. $\delta_{1, 3} = \pi^4\operatorname{edeg}G(2,4)$). Also note that in the linked paper, in "Theorem 3" you have the same typo. I will calculate some digits and update the question. | |
| Nov 5, 2020 at 11:03 | comment | added | Leo | Thank you for pointing it out! The correct form should be in Proposition 24 (without the "$u$" in the numerator of $G$). I edited the answer. I hope this will give better results. | |
| Nov 5, 2020 at 11:01 | history | edited | Leo | CC BY-SA 4.0 |
Edit 1: typo in G and ref
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| Nov 4, 2020 at 11:33 | comment | added | Brendan McKay | Maple evaluates $F(u)$ and $G(u)$ in terms of elliptic functions. | |
| Nov 4, 2020 at 11:29 | comment | added | Moritz Firsching | I'm trying to use your formula, so far without much luck gist.github.com/mo271/649b781bb362931de9483c41214345eb I can calculate the integral, but I get 9.173... | |
| Nov 4, 2020 at 10:52 | comment | added | Moritz Firsching | In the linked paper, in Proposition 24, there is no "$u$" in the numerator of the integrand in the definition of $G(u)$. Is this a typo? | |
| Nov 4, 2020 at 10:21 | comment | added | Moritz Firsching | Bravo! I'm still interested in seeing if this is actually easier to evaluate numerically.. | |
| Nov 4, 2020 at 9:50 | review | Late answers | |||
| Nov 4, 2020 at 10:53 | |||||
| Nov 4, 2020 at 9:34 | review | First posts | |||
| Nov 4, 2020 at 10:00 | |||||
| Nov 4, 2020 at 9:33 | history | answered | Leo | CC BY-SA 4.0 |