Timeline for Is there an integer decomposing into four particular Pythagorean triplets?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Jan 5, 2021 at 6:55 | answer | added | poetasis | timeline score: 1 | |
| S Nov 13, 2020 at 20:02 | history | bounty ended | CommunityBot | ||
| S Nov 13, 2020 at 20:02 | history | notice removed | CommunityBot | ||
| Nov 5, 2020 at 22:53 | comment | added | Yaakov Baruch | I checked for $c=5^3\times 13\times 17\times 29\times 37\times 41\times 53\times 61$, which decomposes in 7654 ways, and did not even find 3 triples $(a_1,b_1,c), (a_2,b_2,c), (a_3,b_3,c)$ with $a_1 b_1+a_2 b_2=a_3 b_3$ - never mind a fourth triple! | |
| S Nov 5, 2020 at 18:05 | history | bounty started | CommunityBot | ||
| S Nov 5, 2020 at 18:05 | history | notice added | user155516 | Draw attention | |
| Oct 31, 2020 at 4:55 | comment | added | individ | Solutions can be written as follows. artofproblemsolving.com/community/… $p,s-$ Think of it as A Pythagorean triple. And then do the conversion..... maybe something will happen. | |
| Oct 30, 2020 at 23:00 | history | edited | user44191 | CC BY-SA 4.0 |
edited body
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| Oct 30, 2020 at 22:10 | history | edited | user155516 | CC BY-SA 4.0 |
added 5 characters in body
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| Oct 30, 2020 at 21:25 | review | First posts | |||
| Oct 31, 2020 at 8:29 | |||||
| Oct 30, 2020 at 21:25 | history | asked | user155516 | CC BY-SA 4.0 |