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Nov 2, 2020 at 10:37 vote accept Maurizio Moreschi
Oct 30, 2020 at 20:57 comment added Maurizio Moreschi Thank you for updating your answer. I am not going to modify the question again, but if with k=2 it's contradictory, then it is clear that I have not manage to get to the right formulation of what I want to ask yet (I have namely concrete examples of the situation I have in mind, when k=2).
Oct 30, 2020 at 18:59 history edited Christian Remling CC BY-SA 4.0
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Oct 30, 2020 at 14:48 comment added Christian Remling @MaurizioMoreschi: Yes, no problem, thanks for clarifying. I was just trying to make a general comment (especially since this is a widespread and somewhat unfortunate phenomenon on MO).
Oct 30, 2020 at 12:52 comment added Maurizio Moreschi You are perfectly right, sorry. I didn't realize at all that there were something wrong with the formulation until reading your answer. The current formulation is what I really meant.
Oct 30, 2020 at 12:47 history edited Christian Remling CC BY-SA 4.0
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Oct 30, 2020 at 12:46 comment added Christian Remling If I may make a general comment, please try to avoid this kind of moving target question, where you change it to a different question after the first version has been answered.
Oct 30, 2020 at 12:44 comment added Christian Remling @MaurizioMoreschi: Now it's a different situation, of course. There's a huge difference between "for all $x\in H_0$" (the question you asked originally) and "there is an ONB of $H_0$ for which..." (the edited version).
Oct 30, 2020 at 11:24 comment added Maurizio Moreschi The case $k=1$ is indeed not very interesting. I have worked it out and added to the question. The positiveness of local spectral measures at zero would indeed imply that $T=0$ in the case $k=1$.
Oct 30, 2020 at 9:34 comment added Maurizio Moreschi For the case $k=1$, I don't have any interesting example, so it might be that it would follow that $T=0$. In any case, I am actually mostly interested in the case $k\ge 2$ (in the example in the previous comment one has $k=2$).
Oct 30, 2020 at 8:15 comment added Maurizio Moreschi I have adapted the formulation of the question a little to eliminate the only potential problem I could see. As an example, you can take the l^2 adjacency operator of a (c,d)-biregular tree with $c\ne d$.
Oct 30, 2020 at 7:50 comment added Maurizio Moreschi Mmm, that's something weird going on. This question is motivated by many explicit examples that come up from my research in which clearly $T\ne 0$ and $H\ne H_0$.
Oct 29, 2020 at 23:38 history answered Christian Remling CC BY-SA 4.0