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Oct 29, 2020 at 9:53 vote accept Leo Moos
Oct 28, 2020 at 22:29 comment added RBega2 @LeoMoos I'm not sure if there is a simple way. It's possible you could quotient out by the period translation and see if something about the flux or torque of the end of the resulting surface gave it to you, but I don't know if that works off the top of my head. Alternatively, you could observe that as the wings of the Scherk family collapse to one another, an appropriate rescaling gives the catenoid and this is logarithmicaly offset from the tangent plane.
Oct 28, 2020 at 20:57 comment added Leo Moos That's a fine explanation, thanks! Is there a simple way to see that the non-orthogonal Scherk surfaces must be offset by a positive amount?
Oct 28, 2020 at 19:17 history answered RBega2 CC BY-SA 4.0