Timeline for Prove the the interval of selected elements in a list is exactly 4 [closed]
Current License: CC BY-SA 4.0
12 events
when toggle format | what | by | license | comment | |
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Oct 27, 2020 at 14:12 | history | closed |
Dmitri Pavlov user44191 Dirk Philippe Gaucher Amir Sagiv |
Not suitable for this site | |
Oct 25, 2020 at 16:01 | review | Close votes | |||
Oct 27, 2020 at 14:12 | |||||
Oct 25, 2020 at 15:41 | vote | accept | kennysliding | ||
Oct 25, 2020 at 15:41 | comment | added | RobPratt | What is the source of the problem? | |
Oct 25, 2020 at 15:38 | comment | added | kennysliding | Thank you for your answer, but since there are 4 elements, namely B, C, D, E in between A and F, this makes A and F 4 elements apart. But thank you for your answer and I will be more aware to post on the appropriate site next time. | |
Oct 25, 2020 at 15:38 | comment | added | RobPratt | OK, I missed that in the example. I suspect that the OP misinterpreted what 4 apart means. | |
Oct 25, 2020 at 15:36 | comment | added | Tony Huynh | Not according to the definition, 4 elements apart means $a-b=5$ (since $A$ and $F$ are $4$ elements apart). | |
Oct 25, 2020 at 15:35 | comment | added | RobPratt | @TonyHuynh Elements 1 and 5 in your solution are exactly 4 apart. | |
Oct 25, 2020 at 15:34 | comment | added | Tony Huynh | This is not really appropriate for this site, but since I am here, the claim is false. If you name the elements $1, \dots, 115$, then the set of elements that are $1,2,3,4,$ or $5$ (mod $10$) is a counterexample. On the other hand, it is true if you take at least 61 elements. Colour the elements (mod 5). Since each colour class has 23 elements, you can choose at most 12 elements from each colour class. | |
Oct 25, 2020 at 15:34 | answer | added | RobPratt | timeline score: 2 | |
Oct 25, 2020 at 15:11 | review | First posts | |||
Oct 25, 2020 at 15:39 | |||||
Oct 25, 2020 at 15:05 | history | asked | kennysliding | CC BY-SA 4.0 |