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Oct 27, 2020 at 14:12 history closed Dmitri Pavlov
user44191
Dirk
Philippe Gaucher
Amir Sagiv
Not suitable for this site
Oct 25, 2020 at 16:01 review Close votes
Oct 27, 2020 at 14:12
Oct 25, 2020 at 15:41 vote accept kennysliding
Oct 25, 2020 at 15:41 comment added RobPratt What is the source of the problem?
Oct 25, 2020 at 15:38 comment added kennysliding Thank you for your answer, but since there are 4 elements, namely B, C, D, E in between A and F, this makes A and F 4 elements apart. But thank you for your answer and I will be more aware to post on the appropriate site next time.
Oct 25, 2020 at 15:38 comment added RobPratt OK, I missed that in the example. I suspect that the OP misinterpreted what 4 apart means.
Oct 25, 2020 at 15:36 comment added Tony Huynh Not according to the definition, 4 elements apart means $a-b=5$ (since $A$ and $F$ are $4$ elements apart).
Oct 25, 2020 at 15:35 comment added RobPratt @TonyHuynh Elements 1 and 5 in your solution are exactly 4 apart.
Oct 25, 2020 at 15:34 comment added Tony Huynh This is not really appropriate for this site, but since I am here, the claim is false. If you name the elements $1, \dots, 115$, then the set of elements that are $1,2,3,4,$ or $5$ (mod $10$) is a counterexample. On the other hand, it is true if you take at least 61 elements. Colour the elements (mod 5). Since each colour class has 23 elements, you can choose at most 12 elements from each colour class.
Oct 25, 2020 at 15:34 answer added RobPratt timeline score: 2
Oct 25, 2020 at 15:11 review First posts
Oct 25, 2020 at 15:39
Oct 25, 2020 at 15:05 history asked kennysliding CC BY-SA 4.0