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Dec 15, 2020 at 15:37 history edited Pedja CC BY-SA 4.0
Added new upper bound for verified n
Oct 27, 2020 at 3:17 vote accept Pedja
Dec 15, 2020 at 17:24
Oct 26, 2020 at 20:39 answer added Max Alekseyev timeline score: 8
Oct 25, 2020 at 15:26 comment added Emil Jeřábek Ok, thanks. Then I expect the original claim not to work either.
Oct 25, 2020 at 12:17 comment added Pedja @EmilJeřábek No,it doesn't work...for $c=-1$ the smallest counterexample is $2047$. See here
Oct 25, 2020 at 12:04 comment added Emil Jeřábek Is there any reason to expect that $c$'s being smallest plays any role? If I drop that condition, I can take, say, an odd prime $c$ congruent to $-1$ mod $n$ by Dirichlet's theorem. So, does the test work if I just take $c=-1$?
Oct 25, 2020 at 10:18 comment added Wojowu One implication is easy: if $n$ is prime, then in $\mathbb Z[i]$ we have $(c+i)^n\equiv c^n+i^n\equiv c-i\pmod n$.
Oct 25, 2020 at 8:32 history edited Wlod AA CC BY-SA 4.0
a superfluous "odd"
Oct 25, 2020 at 5:25 history asked Pedja CC BY-SA 4.0