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Sep 2, 2010 at 15:00 comment added Pietro Majer (with $\epsilon$ large enough)
Sep 2, 2010 at 14:33 comment added Pietro Majer Indeed for every Banach space $X$ and every bounded linear functional $f$, there is an equivalent norm of $X$ producing a unit ball such that $f$ has multiple maximum points there (just take $\max\{\|x\|,\epsilon |\langle f,x\rangle |\}$)
Sep 2, 2010 at 14:06 comment added Bill Johnson Uniqueness is equivalent to strict convexity of the ball, Piero: If $f$ attains its max at two points $x$ and $y$, then it attains it at everything on the line segment joining $x$ and $y$. On the other hand, if the sphere contains a line segment, you can define a norm one linear functional $f$ on the two dimensional subspace spanned by the endpoints of the segment s.t. the segment is contained in $[f=1]$ and use Hahn-Banach to extend the functional to the entire space.
Sep 2, 2010 at 12:16 comment added Piero D'Ancona Uniqueness seems to fail even in finite dimensional cases (think of $R^2$ with sup norm) and might be related to uniform convexity -- just a guess
Sep 2, 2010 at 11:22 history edited Jonas T CC BY-SA 2.5
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Sep 2, 2010 at 11:16 history edited Jonas T CC BY-SA 2.5
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Sep 2, 2010 at 11:11 comment added Jonas T This seems to be James' article about this: springerlink.com/content/07411341j5792482
Sep 2, 2010 at 11:05 comment added Andrew Stacey +1 not particularly for the question but because that theorem is something I'd been wondering about recently but didn't know that someone had proven it! Don't happen to have a reference for it, do you?
Sep 2, 2010 at 10:48 vote accept CommunityBot moved from User.Id=5295 by developer User.Id=481663
Sep 2, 2010 at 10:45 answer added Pietro Majer timeline score: 9
Sep 2, 2010 at 10:35 history asked Jonas T CC BY-SA 2.5