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Oct 24, 2020 at 20:41 comment added Denis Nardin Simpler is in the eye of the beholder, but I would argue that computing $H_n(S^n)$ is much easier than $\pi_nS^n$ (that requires some proof of Freudenthal's suspension theorem -- say with Blakers-Massey). In general I find it very hard to argue that Blakers-Massey is a "simpler" result than the Mayer-Vietoris les.
Oct 24, 2020 at 20:06 comment added Benoît Kloeckner @DenisNardin: sure, but is it obviously simpler?
Oct 24, 2020 at 18:37 comment added Denis Nardin You can easily prove invariance of domain using homology groups instead...
S Oct 24, 2020 at 18:36 history answered Benoît Kloeckner CC BY-SA 4.0
S Oct 24, 2020 at 18:36 history made wiki Post Made Community Wiki by Benoît Kloeckner