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Oct 20, 2020 at 19:20 comment added Joseph Gordon The upper bound, I think, is given by Fisher's inequality (which is stated in a various number of ways, see e.g. this for relevant statement)
Oct 20, 2020 at 14:23 vote accept Dominic van der Zypen
Oct 20, 2020 at 13:09 answer added Antoine Labelle timeline score: 5
Oct 20, 2020 at 12:55 history edited Dominic van der Zypen CC BY-SA 4.0
forgot the $|..|$ in the definition of the Hamming distance
Oct 20, 2020 at 12:52 comment added Dominic van der Zypen That's right, thanks @JosephGordon, I should have restricted the question to even $k$
Oct 20, 2020 at 12:50 comment added Joseph Gordon Note that for odd $k$ the graph is bipartite (color by parity of the number of $1$'s). For even $k$ quantity $\omega(G_{n,k})-1$ corresponds to the maximal number of $k$-subsets of $[n]$ with pairwise intersections of size $k/2$ (clique containing $(0,0,...)$ looks in such a way).
Oct 20, 2020 at 12:34 answer added Steve Huntsman timeline score: 2
Oct 20, 2020 at 11:14 comment added Gordon Royle Not 3. This is the famous result of Payan that cubelike graphs never have chromatic number 3 (or clique number). Your graphs, called “distance graphs” by Payan are special cases of cubelike graphs. Start here core.ac.uk/download/pdf/82733314.pdf for more including a reference to a paper by Dvorak et al.
Oct 20, 2020 at 10:26 history asked Dominic van der Zypen CC BY-SA 4.0