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Oct 19, 2020 at 23:38 comment added Robert Israel Slightly more generally, suppose $A$ is a $2 \times 2$ positive definite symmetric matrix. The partial derivative of $(A^{-1})_{1,1}$ with respect to the entry $a_{1,2}$ is $2 a_{12} a_{22}/(\det A)^2$. Thus if $a_{12} > 0$, increasing $a_{12}$ (and keeping $a_{21}=a_{12}$) increases $(A^{-1})_{11}$ rather than decreasing it.
Oct 19, 2020 at 18:32 vote accept user812951
Oct 19, 2020 at 16:24 comment added Carlo Beenakker sorry, no idea why this inequality should hold in some general sense.
Oct 19, 2020 at 16:15 history edited Carlo Beenakker CC BY-SA 4.0
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Oct 19, 2020 at 15:54 comment added user812951 Can I take the liberty to ask you here itself, will the inequality hold true if we put any more conditions on A? Even a hint would be enough.
Oct 19, 2020 at 14:30 history answered Carlo Beenakker CC BY-SA 4.0