Timeline for Totally ramified extensions of p-adic fields
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Oct 15, 2020 at 11:09 | comment | added | Chris Wuthrich | No, because the tame inertia group is cyclic. | |
| Oct 15, 2020 at 10:50 | comment | added | reuns | I missed you said totally ramified, thus always no. | |
| Oct 15, 2020 at 10:45 | history | edited | A. Maarefparvar | CC BY-SA 4.0 |
added 7 characters in body
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| Oct 15, 2020 at 10:43 | comment | added | reuns | Yes if $q\nmid p-1$, otherwise no: $p\nmid [K:\Bbb{Q}]$ means that $K$ is a tamely ramified extension, thus $K\subset T=\bigcup_{p\nmid n}\Bbb{Q}_p(\zeta_n,p^{1/n})$, and $T\cap \Bbb{Q}_p^{ab}=\bigcup_{p\nmid n}\Bbb{Q}_p(\zeta_n,p^{1/(p-1)})$ (for $p$ odd) | |
| Oct 15, 2020 at 10:38 | history | asked | A. Maarefparvar | CC BY-SA 4.0 |