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Oct 15, 2020 at 5:28 vote accept Bernard
Oct 15, 2020 at 1:27 answer added fedja timeline score: 1
Oct 14, 2020 at 22:46 comment added Bernard $k>0$ since 1/k is the characteristic time of the lag.
Oct 14, 2020 at 21:18 answer added Arthur B timeline score: 0
Oct 14, 2020 at 21:11 comment added fedja You should be a bit careful about how you state it because for $a=bk$, the eigenvalue equation factors as $(\lambda-k)(\lambda^2+bk)=0$, which is a borderline case as one would expect only if $k> 0, b>0$. Do you always assume that $a,b,k$ are all positive and are interested in the stability condition under that assumption?
Oct 14, 2020 at 20:22 history asked Bernard CC BY-SA 4.0