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Oct 29, 2020 at 12:58 vote accept Consider Non-Trivial Cases
S Oct 12, 2020 at 20:21 history suggested xion3582 CC BY-SA 4.0
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Oct 12, 2020 at 18:52 review Suggested edits
S Oct 12, 2020 at 20:21
Oct 12, 2020 at 16:58 comment added Consider Non-Trivial Cases @WillJagy that was very helpful, this time I was looking for a general solution.
Oct 12, 2020 at 16:41 comment added Will Jagy @Servaes first posted at MSE math.stackexchange.com/questions/3820129/…
Oct 12, 2020 at 7:38 comment added user75451 This is really not a question for MO, but for MSE.
Oct 12, 2020 at 7:10 history became hot network question
Oct 12, 2020 at 7:02 comment added GH from MO @Andrew: Every prime $p\equiv 2\pmod{3}$ is represented by $x^2+y^2$ or $3x^2-y^2$. See my response for more detail.
Oct 12, 2020 at 6:43 history edited YCor CC BY-SA 4.0
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Oct 12, 2020 at 6:08 history edited Consider Non-Trivial Cases CC BY-SA 4.0
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Oct 12, 2020 at 6:04 answer added GH from MO timeline score: 14
Oct 12, 2020 at 4:38 comment added Consider Non-Trivial Cases @GerryMyerson you are correct, then what is the solution and where I can find related results?
Oct 12, 2020 at 4:36 comment added Consider Non-Trivial Cases @WillSawin yes overlap is allowed, then, for example, how we find quadratic forms that represents all primes defined by $p \equiv 2 \pmod 3$?
Oct 12, 2020 at 4:31 history edited Consider Non-Trivial Cases CC BY-SA 4.0
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Oct 12, 2020 at 4:02 comment added Gerry Myerson I read the question as permitting overlap. I think the question is, is there a finite set of (preferably irreducible) binary quadratic forms such that every prime is represented by at least one of the forms in the set?
Oct 11, 2020 at 23:37 comment added Will Sawin You can certainly get all primes if you are willing to accept overlap between the different quadratic forms.
Oct 11, 2020 at 23:25 comment added Will Sawin If a quadratic form represents $p$, then the discriminant $b^2 -4ac$ of the form is a perfect square modulo $p$. (Proof: The discriminant is invariant under change of variables. Because the form represents $p$, we can change variables so that $a=p$.) So indeed no non-split form represents all primes and sets like the set of primes congruent to $2$ mod $3$ can never be represented.
Oct 11, 2020 at 23:11 comment added Wojowu Actually on second reading, you didn't ask for the form to only represent the forms of specific residue. In that case there are some trivial examples, like the form $xy$, or $x^2-y^2$. I'm not sure if you can do with only irreducible forms.
Oct 11, 2020 at 23:08 comment added Wojowu I'm fairly sure that for any primitive quadratic form and any $m>0$, the form represents infinitely many primes which are $1\pmod m$. This should follow from Chebotarev's density theorem. Therefore there cannot be such a form which only represents non-1 residues modulo a number.
Oct 11, 2020 at 22:56 history asked Consider Non-Trivial Cases CC BY-SA 4.0